You're trying to use a dict as a key to another dict or in a set. That does not work because the keys have to be hashable. As a. Skip to content >>> some_dict[dict_key] = True Traceback (most recent call last): File "", line 1, in TypeError: unhashable type: 'dict' To use a dict as a key you need to turn it into something NetworkX errors while adding nodes: "unhashable type: 'dict'" and "ValueError: too many values to unpack (expected 2)" 0 networkx and dict_values causing float argument error
How to Fix - TypeError unhashable type 'dict' - Data Science Parichay
1 Answer. Sorted by: 1. Since [HOST] is really for simple logical operations, you cannot access Series methods of columns. As workaround, consider assign of flags to then query against. Consider also [HOST]e for 1. TBH, I find it confusing that dictionaries and sets use basically identical syntax. With two elements, the only thing that makes it possible to distinguish between a dictionary and a set is the symbol in the middle:: or, Even worse, {} constructs an empty dictionary, while it seems more logical for it to construct a set. – ForceBru Traceback (most recent call last): File "[HOST]", line 26, in zipping = dict(zip(datelist, matchhref)) TypeError: unhashable type: 'list' I want to make dictionary from two lists (datelist and matchhref), but somehow when I use zip(), it returns list instead of tuple. Here's my code In this article, you are going to learn about how to fix TypeError: unhashable type: ‘dict’ in python. In python, dictionaries are considered as the The “TypeError: unhashable type: ‘dict'” error typically occurs when you use a dictionary as a key in a Python set. This error message indicates that you’ve Learn about alternatives to dictionaries for unhashable types and to avoid “TypeError: Unhashable Type: dict”. Understanding TypeErrors in Python.
How to Handle TypeError: Unhashable Type ‘Dict’ Exception in …
Solution 3: Use a Different Data Structure. If converting the dictionary to a hashable type isn’t an option, the second solution is using a different data structure that can manage unhashable types, like a list. For example, we can use a list of dictionaries instead of a dictionary of dictionaries The variable v in this expression: key, v = spl [0], spl [1:] is a list with the remaining values. You cannot use a list to index a dictionary, so this: del dic [v] will fail. Looking at the code logic, you probably want to do this anyway: for value in v: if 3 Answers. Try this code. The main idea is convert the [v]+ [i] values in dict1 and dict2 to tuple, then calculate the difference of dict1 and dict2. Finally, convert the tuple type values back to list. ret = {} third_value_list = [0,1] for i in third_value_list: #print i num_list = [1,2] val_list = [0,1] dict1 = dict ((k, tuple ([v]+ [i Python dictionary: TypeError: unhashable type: 'list' Ask Question. Asked 12 years, 2 months ago. Modified 1 year, 11 months ago. Viewed k Dict items support set-like operations, yes, but they are not sets. You cannot have anything unhashable in a set (and tuple with a list inside items is obviuosly unhashable). You can, of course, have unhashable values in a dictionary, and this does not restirct "set-like" operations