Sorted by: 3. There are problems with your code, for example in this selection they are all present: [HOST](left[0]) left = [HOST](1) This should be: [HOST]([HOST](0)) The problems are: Python lists use 0-based indexing so left [0] is the first element of a list not left [1] so [HOST] (0) pops the first element while left Thanks for contributing an answer to Stack Overflow! Please be sure to answer the [HOST]e details and share your research! But avoid . Asking for help, clarification, or responding to other answers I get the IndexError: string index out of range message for any words after "g". Shouldn't the else statement catch it? I don't get why it doesn't, because if I remove the brackets [] from word[0], it works. #2: last word not printing # syntax generates a constant code object corresponding to the one # of the nested function's As the nested function may itself need # global variables, we need to introspect its code, extract its # globals, (look for code object in it's co_consts attribute..) and # add the result to code_globals IndexError: tuple index Modified 11 years, 3 months ago. Viewed 2k times. 1. Line 6 of this code produces a "IndexError: string index out of range". I assume that when I ask "if line [6] Because you index p[1] even when p might contain a single element; you have to make sure that p[1] exists. You probably also want to say count += 1, not count+1, which doesn't seem to do any work in the code you gave.(I'm assuming count and result are global variables; otherwise the code makes no sense.). Here's a working code: count = 1 result Nums = sample (range (0,63),8) This means: choose 8 values that are within the range between 0 and 63, not inclusive - which you will then use to index into alpha. This is needlessly complex. Just sample alpha directly: letters = sample (alpha, 8) That's how the method is supposed to work. There is nothing magic about range One way to do this is to check the index number if it’s less than the length of the string as follows: my_str = "Hello" n = 5 if n
Python: IndexError: list index out of range - Stack Overflow
Summary: Learn how to identify and fix the "IndexError: string index out of range" in Python 3. Understand the causes and explore solutions to resolve this c You signed in with another tab or window. Reload to refresh your session. You signed out in another tab or window. Reload to refresh your session. You switched IndexError: list index out of range Here is my code. count = 0 count2 = 1 rlength = range(len(records)) for i in rlength: ex = records[count].id for bla in rlength: if [HOST](ex, records[count2].id)!= None: print records[count2].id count2 += 1 count += 1 count2 = count + 1 After navigating from page A to page B, if a user goes back is Letter_index = [HOST]t(zero, lenght+1) Unlike range(a, b), that gives numbers from a upto b, not including b, i.e. a index = [HOST]t(zero, lenght - 1) Or even better, random_symbol = [HOST](symbols) Your Python code was pretty broken; please review my attempt to fix it. Going forward, probably notice that you get a preview of what your post will look like below the The Python IndexError: list index out of range can be fixed by making sure any elements accessed in a list are within the index range of the list. This can be done
Python - IndexError: tuple index out of range when creating …
1) @snakecharmerb or a list or a dict see Parameters.2) The code in your traceback does not match the code in your example: [HOST]e(sql, t) vs [HOST]e(sql, genre) 3) The issue is that psycopg2 when using % is assuming the values are a sequence. A string by itself is a sequence and what you are seeing is: s = '' s[0] IndexError: string November 15, In this tutorial, you’ll learn how all about the Python list index out of range error, including what it is, why it occurs, and how to resolve it. The IndexError is @Nguaial The list type is subscriptable, but you can only access elements that already exist - you can't create an element by attempting to write to an index that is out of range. j[0] = "foo" will work if the list already has at least one element