TIMESTAMPS introduction key points plan to prove proof of theorem how it is asked in examInversion Transformation Video Link: https://y Video transcript. I want to do a quick argument, or proof, as to why the diagonals of a rhombus are perpendicular. So remember, a rhombus is just a parallelogram A rhombus has four sides of equal lengths. It has two pairs of equal angles. The opposite sides are parallel. The diagonals bisect each other at right angles
Finding half a diagonal in a rhombus using trigonometric ratios?
Video transcript. I want to do a quick argument, or proof, as to why the diagonals of a rhombus are perpendicular. So remember, a rhombus is just a parallelogram where all four sides are equal. In fact, if all four sides are equal, it has to be a parallelogram 11 years ago. Wouldn't when he talks about the line forming a straight angle, isn't that kind of arbitrary? Since there are two line segments, how can you tell if one 11 years ago. Wouldn't when he talks about the line forming a straight angle, isn't that kind of arbitrary? Since there are two line segments, how can you tell if one isn't slightly off from the other, creating a vastly obtuse degree angle? Would what he had said be equivalent to the protractor postulate? •. (25 votes) [HOST]
How do you prove that the diagonals of a rhombus are perpendicular …
AD= CD [Sides of a rhombus] ∴ ΔAOD≅ΔCOD [SSS congruency rule] ⇒ ∠AOD= ∠COD (i) [CPCT] But, ∠AOD+∠COD= ∘ [Linear pair, since AOC is a straight line] So, 2∠AOD=∘ [From (i)] ⇒ ∠AOD= 90∘. ⇒ the diagonals AC and BD are perpendicular. Suggest Corrections The diagonals of a rhombus are perpendicular. Teacher Note: Some students may notice there are special cases in which rectangles, parallelograms, and K subscribers. views 1 year ago. Prove that the diagonals of a rhombus are perpendicular bisectors of each other. 📲PW App Link -